Formula to find sum of n consecutive square numbers = n*(n+1)*(2n+1)/6
Step 1 : Find the sum of first 20 consecutive square numbers
Step 2 : n= 20
Step3 :n*(n+1)*(2n+1)/6 = 20*(20+1)*(2*20 +1)/6 = 20*21*41/6
Step 4 : 2870 (It’s the final answer)
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